Solve 4/3+4/9-1/5

$$\frac { 4 } { 3 } + \frac { 4 } { 9 } - \frac { 1 } { 5 }$$

Evaluate

$$\frac{71}{45}\approx 1.577777778$$

Solution Steps

Least common multiple of 3 and 9 is 9. Convert \frac{4}{3} and \frac{4}{9} to fractions with denominator 9.

$$\frac{12}{9}+\frac{4}{9}-\frac{1}{5}$$

Since \frac{12}{9} and \frac{4}{9} have the same denominator, add them by adding their numerators.

$$\frac{12+4}{9}-\frac{1}{5}$$

Add 12 and 4 to get 16.

$$\frac{16}{9}-\frac{1}{5}$$

Least common multiple of 9 and 5 is 45. Convert \frac{16}{9} and \frac{1}{5} to fractions with denominator 45.

$$\frac{80}{45}-\frac{9}{45}$$

Since \frac{80}{45} and \frac{9}{45} have the same denominator, subtract them by subtracting their numerators.

$$\frac{80-9}{45}$$

Subtract 9 from 80 to get 71.

$$\frac{71}{45}$$

Factor

$$\frac{71}{3 ^ {2} \cdot 5} = 1\frac{26}{45} = 1.5777777777777777$$