Solve 4/2-frac{1{3}}-4/2+frac{1{3}}

$$\frac { 4 } { 2 - \frac { 1 } { 3 } } - \frac { 4 } { 2 + \frac { 1 } { 3 } }$$

Evaluate

$$\frac{24}{35}\approx 0.685714286$$

Solution Steps

Convert 2 to fraction \frac{6}{3}.

$$\frac{4}{\frac{6}{3}-\frac{1}{3}}-\frac{4}{2+\frac{1}{3}}$$

Since \frac{6}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4}{\frac{6-1}{3}}-\frac{4}{2+\frac{1}{3}}$$

Subtract 1 from 6 to get 5.

$$\frac{4}{\frac{5}{3}}-\frac{4}{2+\frac{1}{3}}$$

Divide 4 by \frac{5}{3} by multiplying 4 by the reciprocal of \frac{5}{3}.

$$4\times \frac{3}{5}-\frac{4}{2+\frac{1}{3}}$$

Express 4\times \frac{3}{5} as a single fraction.

$$\frac{4\times 3}{5}-\frac{4}{2+\frac{1}{3}}$$

Multiply 4 and 3 to get 12.

$$\frac{12}{5}-\frac{4}{2+\frac{1}{3}}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{12}{5}-\frac{4}{\frac{6}{3}+\frac{1}{3}}$$

Since \frac{6}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{12}{5}-\frac{4}{\frac{6+1}{3}}$$

Add 6 and 1 to get 7.

$$\frac{12}{5}-\frac{4}{\frac{7}{3}}$$

Divide 4 by \frac{7}{3} by multiplying 4 by the reciprocal of \frac{7}{3}.

$$\frac{12}{5}-4\times \frac{3}{7}$$

Express 4\times \frac{3}{7} as a single fraction.

$$\frac{12}{5}-\frac{4\times 3}{7}$$

Multiply 4 and 3 to get 12.

$$\frac{12}{5}-\frac{12}{7}$$

Least common multiple of 5 and 7 is 35. Convert \frac{12}{5} and \frac{12}{7} to fractions with denominator 35.

$$\frac{84}{35}-\frac{60}{35}$$

Since \frac{84}{35} and \frac{60}{35} have the same denominator, subtract them by subtracting their numerators.

$$\frac{84-60}{35}$$

Subtract 60 from 84 to get 24.

$$\frac{24}{35}$$

Factor

$$\frac{2 ^ {3} \cdot 3}{5 \cdot 7} = 0.6857142857142857$$