Solve 4/13(7/3+2-1/4)=

$$\frac { 4 } { 13 } ( \frac { 7 } { 3 } + 2 - \frac { 1 } { 4 } ) =$$

Evaluate

$$\frac{49}{39}\approx 1.256410256$$

Solution Steps

Convert 2 to fraction \frac{6}{3}.

$$\frac{4}{13}\left(\frac{7}{3}+\frac{6}{3}-\frac{1}{4}\right)$$

Since \frac{7}{3} and \frac{6}{3} have the same denominator, add them by adding their numerators.

$$\frac{4}{13}\left(\frac{7+6}{3}-\frac{1}{4}\right)$$

Add 7 and 6 to get 13.

$$\frac{4}{13}\left(\frac{13}{3}-\frac{1}{4}\right)$$

Least common multiple of 3 and 4 is 12. Convert \frac{13}{3} and \frac{1}{4} to fractions with denominator 12.

$$\frac{4}{13}\left(\frac{52}{12}-\frac{3}{12}\right)$$

Since \frac{52}{12} and \frac{3}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4}{13}\times \frac{52-3}{12}$$

Subtract 3 from 52 to get 49.

$$\frac{4}{13}\times \frac{49}{12}$$

Multiply \frac{4}{13} times \frac{49}{12} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4\times 49}{13\times 12}$$

Do the multiplications in the fraction \frac{4\times 49}{13\times 12}.

$$\frac{196}{156}$$

Reduce the fraction \frac{196}{156} to lowest terms by extracting and canceling out 4.

$$\frac{49}{39}$$

Factor

$$\frac{7 ^ {2}}{3 \cdot 13} = 1\frac{10}{39} = 1.2564102564102564$$