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\frac{1}{3}\times \frac{2}{1}=\frac{8}{12}\text{ and }\frac{8}{12}=\frac{4}{6}
Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.
\frac{1}{3}\times 2=\frac{8}{12}\text{ and }\frac{8}{12}=\frac{4}{6}
Anything divided by one gives itself.
\frac{2}{3}=\frac{8}{12}\text{ and }\frac{8}{12}=\frac{4}{6}
Multiply \frac{1}{3} and 2 to get \frac{2}{3}.
\frac{2}{3}=\frac{2}{3}\text{ and }\frac{8}{12}=\frac{4}{6}
Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.
\text{true}\text{ and }\frac{8}{12}=\frac{4}{6}
Compare \frac{2}{3} and \frac{2}{3}.
\text{true}\text{ and }\frac{2}{3}=\frac{4}{6}
Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.
\text{true}\text{ and }\frac{2}{3}=\frac{2}{3}
Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.
\text{true}\text{ and }\text{true}
Compare \frac{2}{3} and \frac{2}{3}.
\text{true}
The conjunction of \text{true} and \text{true} is \text{true}.