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\frac{4\left(\sqrt{3}-2\right)}{\left(\sqrt{3}+2\right)\left(\sqrt{3}-2\right)}
Rationalize the denominator of \frac{4}{\sqrt{3}+2} by multiplying numerator and denominator by \sqrt{3}-2.
\frac{4\left(\sqrt{3}-2\right)}{\left(\sqrt{3}\right)^{2}-2^{2}}
Consider \left(\sqrt{3}+2\right)\left(\sqrt{3}-2\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{4\left(\sqrt{3}-2\right)}{3-4}
Square \sqrt{3}. Square 2.
\frac{4\left(\sqrt{3}-2\right)}{-1}
Subtract 4 from 3 to get -1.
-4\left(\sqrt{3}-2\right)
Anything divided by -1 gives its opposite.
-4\sqrt{3}+8
Use the distributive property to multiply -4 by \sqrt{3}-2.