Solve 4^3/3-2*4^2

$$\frac { 4 ^ { 3 } } { 3 } - 2 \times 4 ^ { 2 }$$

Evaluate

$$-\frac{32}{3}\approx -10.666666667$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$\frac{64}{3}-2\times 4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{64}{3}-2\times 16$$

Multiply 2 and 16 to get 32.

$$\frac{64}{3}-32$$

Convert 32 to fraction \frac{96}{3}.

$$\frac{64}{3}-\frac{96}{3}$$

Since \frac{64}{3} and \frac{96}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{64-96}{3}$$

Subtract 96 from 64 to get -32.

$$-\frac{32}{3}$$

Factor

$$-\frac{32}{3} = -10\frac{2}{3} = -10.666666666666666$$