Solve 4^3+4^3+4^3+4^3/2*2*2*2=?

$$\frac { 4 ^ { 3 } + 4 ^ { 3 } + 4 ^ { 3 } + 4 ^ { 3 } } { 2 \cdot 2 \cdot 2 \cdot 2 } = ?$$

Evaluate

$$16$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$\frac{64+4^{3}+4^{3}+4^{3}}{2\times 2\times 2\times 2}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{64+64+4^{3}+4^{3}}{2\times 2\times 2\times 2}$$

Add 64 and 64 to get 128.

$$\frac{128+4^{3}+4^{3}}{2\times 2\times 2\times 2}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{128+64+4^{3}}{2\times 2\times 2\times 2}$$

Add 128 and 64 to get 192.

$$\frac{192+4^{3}}{2\times 2\times 2\times 2}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{192+64}{2\times 2\times 2\times 2}$$

Add 192 and 64 to get 256.

$$\frac{256}{2\times 2\times 2\times 2}$$

Multiply 2 and 2 to get 4.

$$\frac{256}{4\times 2\times 2}$$

Multiply 4 and 2 to get 8.

$$\frac{256}{8\times 2}$$

Multiply 8 and 2 to get 16.

$$\frac{256}{16}$$

Divide 256 by 16 to get 16.

$$16$$

Factor

$$2^{4}$$