Solve 4^2+5*(9-3^2)/24div(12-3^2)

$$\frac { 4 ^ { 2 } + 5 \times ( 9 - 3 ^ { 2 } ) } { 24 \div ( 12 - 3 ^ { 2 } ) }$$

Evaluate

$$2$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{16+5\left(9-3^{2}\right)}{\frac{24}{12-3^{2}}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{16+5\left(9-9\right)}{\frac{24}{12-3^{2}}}$$

Subtract 9 from 9 to get 0.

$$\frac{16+5\times 0}{\frac{24}{12-3^{2}}}$$

Multiply 5 and 0 to get 0.

$$\frac{16+0}{\frac{24}{12-3^{2}}}$$

Add 16 and 0 to get 16.

$$\frac{16}{\frac{24}{12-3^{2}}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{16}{\frac{24}{12-9}}$$

Subtract 9 from 12 to get 3.

$$\frac{16}{\frac{24}{3}}$$

Divide 24 by 3 to get 8.

$$\frac{16}{8}$$

Divide 16 by 8 to get 2.

$$2$$

Factor

$$2$$