Solve 300^2+2*300*40+40^2/400^2-60^2

$$\frac { 300 ^ { 2 } + 2 \cdot 300 \cdot 40 + 40 ^ { 2 } } { 400 ^ { 2 } - 60 ^ { 2 } }$$

Evaluate

$$\frac{17}{23}\approx 0.739130435$$

Solution Steps

Calculate 300 to the power of 2 and get 90000.

$$\frac{90000+2\times 300\times 40+40^{2}}{400^{2}-60^{2}}$$

Multiply 2 and 300 to get 600.

$$\frac{90000+600\times 40+40^{2}}{400^{2}-60^{2}}$$

Multiply 600 and 40 to get 24000.

$$\frac{90000+24000+40^{2}}{400^{2}-60^{2}}$$

Add 90000 and 24000 to get 114000.

$$\frac{114000+40^{2}}{400^{2}-60^{2}}$$

Calculate 40 to the power of 2 and get 1600.

$$\frac{114000+1600}{400^{2}-60^{2}}$$

Add 114000 and 1600 to get 115600.

$$\frac{115600}{400^{2}-60^{2}}$$

Calculate 400 to the power of 2 and get 160000.

$$\frac{115600}{160000-60^{2}}$$

Calculate 60 to the power of 2 and get 3600.

$$\frac{115600}{160000-3600}$$

Subtract 3600 from 160000 to get 156400.

$$\frac{115600}{156400}$$

Reduce the fraction \frac{115600}{156400} to lowest terms by extracting and canceling out 6800.

$$\frac{17}{23}$$

Factor

$$\frac{17}{23} = 0.7391304347826086$$