Solve 3.1^2/6.17+1.12

$$\frac { 3.1 ^ { 2 } } { 6.17 } + 1.12$$

Evaluate

$$\frac{41301}{15425}\approx 2.677536467$$

Solution Steps

Calculate 3.1 to the power of 2 and get 9.61.

$$\frac{9.61}{6.17}+1.12$$

Expand \frac{9.61}{6.17} by multiplying both numerator and the denominator by 100.

$$\frac{961}{617}+1.12$$

Convert decimal number 1.12 to fraction \frac{112}{100}. Reduce the fraction \frac{112}{100} to lowest terms by extracting and canceling out 4.

$$\frac{961}{617}+\frac{28}{25}$$

Least common multiple of 617 and 25 is 15425. Convert \frac{961}{617} and \frac{28}{25} to fractions with denominator 15425.

$$\frac{24025}{15425}+\frac{17276}{15425}$$

Since \frac{24025}{15425} and \frac{17276}{15425} have the same denominator, add them by adding their numerators.

$$\frac{24025+17276}{15425}$$

Add 24025 and 17276 to get 41301.

$$\frac{41301}{15425}$$

Factor

$$\frac{13 \cdot 353 \cdot 3 ^ {2}}{617 \cdot 5 ^ {2}} = 2\frac{10451}{15425} = 2.6775364667747166$$