Solve for x
x=8
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\frac{3x}{12}=2
Add 5 and 7 to get 12.
\frac{1}{4}x=2
Divide 3x by 12 to get \frac{1}{4}x.
x=2\times 4
Multiply both sides by 4, the reciprocal of \frac{1}{4}.
x=8
Multiply 2 and 4 to get 8.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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