Solve 3x/2+5*frac{sqrt{4}}{2}-1

$$\frac { 3 x } { 2 } + 5 \cdot \frac { \sqrt { 4 } } { 2 } - 1$$

Evaluate

$$\frac{3x}{2}+4$$

Short Solution Steps

Calculate the square root of 4 and get 2.

$$\frac{3x}{2}+5\times \frac{2}{2}-1$$

Divide 2 by 2 to get 1.

$$\frac{3x}{2}+5\times 1-1$$

Multiply 5 and 1 to get 5.

$$\frac{3x}{2}+5-1$$

Subtract 1 from 5 to get 4.

$$\frac{3x}{2}+4$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 4 times \frac{2}{2}.

$$\frac{3x}{2}+\frac{4\times 2}{2}$$

Since \frac{3x}{2} and \frac{4\times 2}{2} have the same denominator, add them by adding their numerators.

$$\frac{3x+4\times 2}{2}$$

Do the multiplications in 3x+4\times 2.

$$\frac{3x+8}{2}$$

Factor

$$\frac{3x+8}{2}$$

Solution Steps

Factor out \frac{1}{2}.

$$\frac{3x+8}{2}$$