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Solve for x (complex solution)
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3x^{2}+7=-2
Multiply both sides by -2.
3x^{2}=-2-7
Subtract 7 from both sides.
3x^{2}=-9
Subtract 7 from -2 to get -9.
x^{2}=\frac{-9}{3}
Divide both sides by 3.
x^{2}=-3
Divide -9 by 3 to get -3.
x=\sqrt{3}i x=-\sqrt{3}i
The equation is now solved.
3x^{2}+7=-2
Multiply both sides by -2.
3x^{2}+7+2=0
Add 2 to both sides.
3x^{2}+9=0
Add 7 and 2 to get 9.
x=\frac{0±\sqrt{0^{2}-4\times 3\times 9}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and 9 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 3\times 9}}{2\times 3}
Square 0.
x=\frac{0±\sqrt{-12\times 9}}{2\times 3}
Multiply -4 times 3.
x=\frac{0±\sqrt{-108}}{2\times 3}
Multiply -12 times 9.
x=\frac{0±6\sqrt{3}i}{2\times 3}
Take the square root of -108.
x=\frac{0±6\sqrt{3}i}{6}
Multiply 2 times 3.
x=\sqrt{3}i
Now solve the equation x=\frac{0±6\sqrt{3}i}{6} when ± is plus.
x=-\sqrt{3}i
Now solve the equation x=\frac{0±6\sqrt{3}i}{6} when ± is minus.
x=\sqrt{3}i x=-\sqrt{3}i
The equation is now solved.