Solve 3s/s^2-36

$$\frac { 3 s } { s ^ { 2 } - 36 }$$

Differentiate w.r.t. s

$$-\frac{3\left(s^{2}+36\right)}{\left(s^{2}-36\right)^{2}}$$

Steps Using Derivative Rule for Quotient

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(s^{2}-36\right)\frac{\mathrm{d}}{\mathrm{d}s}(3s^{1})-3s^{1}\frac{\mathrm{d}}{\mathrm{d}s}(s^{2}-36)}{\left(s^{2}-36\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\frac{\left(s^{2}-36\right)\times 3s^{1-1}-3s^{1}\times 2s^{2-1}}{\left(s^{2}-36\right)^{2}}$$

Do the arithmetic.

$$\frac{\left(s^{2}-36\right)\times 3s^{0}-3s^{1}\times 2s^{1}}{\left(s^{2}-36\right)^{2}}$$

Expand using distributive property.

$$\frac{s^{2}\times 3s^{0}-36\times 3s^{0}-3s^{1}\times 2s^{1}}{\left(s^{2}-36\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{3s^{2}-36\times 3s^{0}-3\times 2s^{1+1}}{\left(s^{2}-36\right)^{2}}$$

Do the arithmetic.

$$\frac{3s^{2}-108s^{0}-6s^{2}}{\left(s^{2}-36\right)^{2}}$$

Combine like terms.

$$\frac{\left(3-6\right)s^{2}-108s^{0}}{\left(s^{2}-36\right)^{2}}$$

Subtract 6 from 3.

$$\frac{-3s^{2}-108s^{0}}{\left(s^{2}-36\right)^{2}}$$

Factor out 3.

$$\frac{3\left(-s^{2}-36s^{0}\right)}{\left(s^{2}-36\right)^{2}}$$

For any term t except 0, t^{0}=1.

$$\frac{3\left(-s^{2}-36\right)}{\left(s^{2}-36\right)^{2}}$$

Evaluate

$$\frac{3s}{s^{2}-36}$$