Solve 3r/p^2*8/pq

$$\frac { 3 r } { p ^ { 2 } } \times \frac { 8 } { p q }$$

Evaluate

$$\frac{24r}{qp^{3}}$$

Solution Steps

Multiply \frac{3r}{p^{2}} times \frac{8}{pq} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3r\times 8}{p^{2}pq}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\frac{3r\times 8}{p^{3}q}$$

Multiply 3 and 8 to get 24.

$$\frac{24r}{p^{3}q}$$

Differentiate w.r.t. r

$$\frac{24}{qp^{3}}$$