Solve for k
k=2
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3\times 3k-2\left(2k-1\right)=12
Multiply both sides of the equation by 6, the least common multiple of 2,3.
9k-2\left(2k-1\right)=12
Multiply 3 and 3 to get 9.
9k-4k+2=12
Use the distributive property to multiply -2 by 2k-1.
5k+2=12
Combine 9k and -4k to get 5k.
5k=12-2
Subtract 2 from both sides.
5k=10
Subtract 2 from 12 to get 10.
k=\frac{10}{5}
Divide both sides by 5.
k=2
Divide 10 by 5 to get 2.
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