Solve 3b^2/a*-3ab^2/6b

$$\frac { 3 b ^ { 2 } } { a } \times - \frac { 3 a b ^ { 2 } } { 6 b }$$

Evaluate

$$-\frac{3b^{3}}{2}$$

Solution Steps

Cancel out 3b in both numerator and denominator.

$$\frac{3b^{2}}{a}\left(-\frac{ab}{2}\right)$$

Multiply \frac{3b^{2}}{a} times -\frac{ab}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3b^{2}ab}{a\times 2}$$

Cancel out a in both numerator and denominator.

$$\frac{-3bb^{2}}{2}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\frac{-3b^{3}}{2}$$

Differentiate w.r.t. b

$$-\frac{9b^{2}}{2}$$