Solve 3b^2+10b-8/b^2+2b-8*b^2-4/3b^2+4b-4

$$\frac { 3 b ^ { 2 } + 10 b - 8 } { b ^ { 2 } + 2 b - 8 } \cdot \frac { b ^ { 2 } - 4 } { 3 b ^ { 2 } + 4 b - 4 }$$

Evaluate

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Short Solution Steps

Factor the expressions that are not already factored in \frac{3b^{2}+10b-8}{b^{2}+2b-8}.

$$\frac{\left(3b-2\right)\left(b+4\right)}{\left(b-2\right)\left(b+4\right)}\times \frac{b^{2}-4}{3b^{2}+4b-4}$$

Cancel out b+4 in both numerator and denominator.

$$\frac{3b-2}{b-2}\times \frac{b^{2}-4}{3b^{2}+4b-4}$$

Factor the expressions that are not already factored in \frac{b^{2}-4}{3b^{2}+4b-4}.

$$\frac{3b-2}{b-2}\times \frac{\left(b-2\right)\left(b+2\right)}{\left(3b-2\right)\left(b+2\right)}$$

Cancel out b+2 in both numerator and denominator.

$$\frac{3b-2}{b-2}\times \frac{b-2}{3b-2}$$

Multiply \frac{3b-2}{b-2} times \frac{b-2}{3b-2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(3b-2\right)\left(b-2\right)}{\left(b-2\right)\left(3b-2\right)}$$

Cancel out \left(b-2\right)\left(3b-2\right) in both numerator and denominator.

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Factor

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