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\frac{3\left(a+b\right)\left(b+c\right)\left(-b+c\right)}{6\left(a+b\right)\left(b+c\right)\left(-b+c\right)}
Factor the expressions that are not already factored.
\frac{1}{2}
Cancel out 3\left(a+b\right)\left(b+c\right)\left(-b+c\right) in both numerator and denominator.