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Real Part
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\frac{\left(3-2i\right)i}{1i^{2}}
Multiply both numerator and denominator by imaginary unit i.
\frac{\left(3-2i\right)i}{-1}
By definition, i^{2} is -1. Calculate the denominator.
\frac{3i-2i^{2}}{-1}
Multiply 3-2i times i.
\frac{3i-2\left(-1\right)}{-1}
By definition, i^{2} is -1.
\frac{2+3i}{-1}
Do the multiplications in 3i-2\left(-1\right). Reorder the terms.
-2-3i
Divide 2+3i by -1 to get -2-3i.
Re(\frac{\left(3-2i\right)i}{1i^{2}})
Multiply both numerator and denominator of \frac{3-2i}{i} by imaginary unit i.
Re(\frac{\left(3-2i\right)i}{-1})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{3i-2i^{2}}{-1})
Multiply 3-2i times i.
Re(\frac{3i-2\left(-1\right)}{-1})
By definition, i^{2} is -1.
Re(\frac{2+3i}{-1})
Do the multiplications in 3i-2\left(-1\right). Reorder the terms.
Re(-2-3i)
Divide 2+3i by -1 to get -2-3i.
-2
The real part of -2-3i is -2.