Solve 3-2+4/3/-2-frac{10{3}}

$$\frac { 3 - 2 + \frac { 4 } { 3 } } { - 2 - \frac { 10 } { 3 } }$$

Evaluate

$$-\frac{7}{16}=-0.4375$$

Solution Steps

Subtract 2 from 3 to get 1.

$$\frac{1+\frac{4}{3}}{-2-\frac{10}{3}}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{3}{3}+\frac{4}{3}}{-2-\frac{10}{3}}$$

Since \frac{3}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{3+4}{3}}{-2-\frac{10}{3}}$$

Add 3 and 4 to get 7.

$$\frac{\frac{7}{3}}{-2-\frac{10}{3}}$$

Convert -2 to fraction -\frac{6}{3}.

$$\frac{\frac{7}{3}}{-\frac{6}{3}-\frac{10}{3}}$$

Since -\frac{6}{3} and \frac{10}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{7}{3}}{\frac{-6-10}{3}}$$

Subtract 10 from -6 to get -16.

$$\frac{\frac{7}{3}}{-\frac{16}{3}}$$

Divide \frac{7}{3} by -\frac{16}{3} by multiplying \frac{7}{3} by the reciprocal of -\frac{16}{3}.

$$\frac{7}{3}\left(-\frac{3}{16}\right)$$

Multiply \frac{7}{3} times -\frac{3}{16} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\left(-3\right)}{3\times 16}$$

Do the multiplications in the fraction \frac{7\left(-3\right)}{3\times 16}.

$$\frac{-21}{48}$$

Reduce the fraction \frac{-21}{48} to lowest terms by extracting and canceling out 3.

$$-\frac{7}{16}$$

Factor

$$-\frac{7}{16} = -0.4375$$