Solve 3-9/x+3/1-frac{5{x+3}}

$$\frac { 3 - \frac { 9 } { x + 3 } } { 1 - \frac { 5 } { x + 3 } }$$

Evaluate

$$\frac{3x}{x-2}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{x+3}{x+3}.

$$\frac{\frac{3\left(x+3\right)}{x+3}-\frac{9}{x+3}}{1-\frac{5}{x+3}}$$

Since \frac{3\left(x+3\right)}{x+3} and \frac{9}{x+3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{3\left(x+3\right)-9}{x+3}}{1-\frac{5}{x+3}}$$

Do the multiplications in 3\left(x+3\right)-9.

$$\frac{\frac{3x+9-9}{x+3}}{1-\frac{5}{x+3}}$$

Combine like terms in 3x+9-9.

$$\frac{\frac{3x}{x+3}}{1-\frac{5}{x+3}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x+3}{x+3}.

$$\frac{\frac{3x}{x+3}}{\frac{x+3}{x+3}-\frac{5}{x+3}}$$

Since \frac{x+3}{x+3} and \frac{5}{x+3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{3x}{x+3}}{\frac{x+3-5}{x+3}}$$

Combine like terms in x+3-5.

$$\frac{\frac{3x}{x+3}}{\frac{x-2}{x+3}}$$

Divide \frac{3x}{x+3} by \frac{x-2}{x+3} by multiplying \frac{3x}{x+3} by the reciprocal of \frac{x-2}{x+3}.

$$\frac{3x\left(x+3\right)}{\left(x+3\right)\left(x-2\right)}$$

Cancel out x+3 in both numerator and denominator.

$$\frac{3x}{x-2}$$

Expand

$$\frac{3x}{x-2}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{x+3}{x+3}.

$$\frac{\frac{3\left(x+3\right)}{x+3}-\frac{9}{x+3}}{1-\frac{5}{x+3}}$$

Since \frac{3\left(x+3\right)}{x+3} and \frac{9}{x+3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{3\left(x+3\right)-9}{x+3}}{1-\frac{5}{x+3}}$$

Do the multiplications in 3\left(x+3\right)-9.

$$\frac{\frac{3x+9-9}{x+3}}{1-\frac{5}{x+3}}$$

Combine like terms in 3x+9-9.

$$\frac{\frac{3x}{x+3}}{1-\frac{5}{x+3}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x+3}{x+3}.

$$\frac{\frac{3x}{x+3}}{\frac{x+3}{x+3}-\frac{5}{x+3}}$$

Since \frac{x+3}{x+3} and \frac{5}{x+3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{3x}{x+3}}{\frac{x+3-5}{x+3}}$$

Combine like terms in x+3-5.

$$\frac{\frac{3x}{x+3}}{\frac{x-2}{x+3}}$$

Divide \frac{3x}{x+3} by \frac{x-2}{x+3} by multiplying \frac{3x}{x+3} by the reciprocal of \frac{x-2}{x+3}.

$$\frac{3x\left(x+3\right)}{\left(x+3\right)\left(x-2\right)}$$

Cancel out x+3 in both numerator and denominator.

$$\frac{3x}{x-2}$$