Solve 3(4x+1)/8-5(2x-1)/12

$$\frac { 3 ( 4 x + 1 ) } { 8 } - \frac { 5 ( 2 x - 1 ) } { 12 }$$

Evaluate

$$\frac{2x}{3}+\frac{19}{24}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 8 and 12 is 24. Multiply \frac{3\left(4x+1\right)}{8} times \frac{3}{3}. Multiply \frac{5\left(2x-1\right)}{12} times \frac{2}{2}.

$$\frac{3\times 3\left(4x+1\right)}{24}-\frac{2\times 5\left(2x-1\right)}{24}$$

Since \frac{3\times 3\left(4x+1\right)}{24} and \frac{2\times 5\left(2x-1\right)}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3\times 3\left(4x+1\right)-2\times 5\left(2x-1\right)}{24}$$

Do the multiplications in 3\times 3\left(4x+1\right)-2\times 5\left(2x-1\right).

$$\frac{36x+9-20x+10}{24}$$

Combine like terms in 36x+9-20x+10.

$$\frac{16x+19}{24}$$

Expand

$$\frac{2x}{3}+\frac{19}{24}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 8 and 12 is 24. Multiply \frac{3\left(4x+1\right)}{8} times \frac{3}{3}. Multiply \frac{5\left(2x-1\right)}{12} times \frac{2}{2}.

$$\frac{3\times 3\left(4x+1\right)}{24}-\frac{2\times 5\left(2x-1\right)}{24}$$

Since \frac{3\times 3\left(4x+1\right)}{24} and \frac{2\times 5\left(2x-1\right)}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3\times 3\left(4x+1\right)-2\times 5\left(2x-1\right)}{24}$$

Do the multiplications in 3\times 3\left(4x+1\right)-2\times 5\left(2x-1\right).

$$\frac{36x+9-20x+10}{24}$$

Combine like terms in 36x+9-20x+10.

$$\frac{16x+19}{24}$$