Solve 3/n^2-2/m^2n=

$$\frac { 3 } { n ^ { 2 } } - \frac { 2 } { m ^ { 2 } n } =$$

Evaluate

$$\frac{3m^{2}-2n}{\left(mn\right)^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of n^{2} and m^{2}n is m^{2}n^{2}. Multiply \frac{3}{n^{2}} times \frac{m^{2}}{m^{2}}. Multiply \frac{2}{m^{2}n} times \frac{n}{n}.

$$\frac{3m^{2}}{m^{2}n^{2}}-\frac{2n}{m^{2}n^{2}}$$

Since \frac{3m^{2}}{m^{2}n^{2}} and \frac{2n}{m^{2}n^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3m^{2}-2n}{m^{2}n^{2}}$$

Factor

$$\left(3-\frac{2n}{m^{2}}\right)\times \left(\frac{1}{n}\right)^{2}$$