Solve 3/8+6/5+1,3=

$$\frac { 3 } { 8 } + \frac { 6 } { 5 } + 1,3 =$$

Evaluate

$$2,875$$

Solution Steps

Least common multiple of 8 and 5 is 40. Convert \frac{3}{8} and \frac{6}{5} to fractions with denominator 40.

$$\frac{15}{40}+\frac{48}{40}+1,3$$

Since \frac{15}{40} and \frac{48}{40} have the same denominator, add them by adding their numerators.

$$\frac{15+48}{40}+1,3$$

Add 15 and 48 to get 63.

$$\frac{63}{40}+1,3$$

Convert decimal number 1,3 to fraction \frac{13}{10}.

$$\frac{63}{40}+\frac{13}{10}$$

Least common multiple of 40 and 10 is 40. Convert \frac{63}{40} and \frac{13}{10} to fractions with denominator 40.

$$\frac{63}{40}+\frac{52}{40}$$

Since \frac{63}{40} and \frac{52}{40} have the same denominator, add them by adding their numerators.

$$\frac{63+52}{40}$$

Add 63 and 52 to get 115.

$$\frac{115}{40}$$

Reduce the fraction \frac{115}{40} to lowest terms by extracting and canceling out 5.

$$\frac{23}{8}$$

Factor

$$\frac{23}{2 ^ {3}} = 2\frac{7}{8} = 2.875$$