Solve 3/8+4/3-2(1/3-2/6)

$$\frac { 3 } { 8 } + \frac { 4 } { 3 } - 2 ( \frac { 1 } { 3 } - \frac { 2 } { 6 } )$$

Evaluate

$$\frac{41}{24}\approx 1.708333333$$

Solution Steps

Least common multiple of 8 and 3 is 24. Convert \frac{3}{8} and \frac{4}{3} to fractions with denominator 24.

$$\frac{9}{24}+\frac{32}{24}-2\left(\frac{1}{3}-\frac{2}{6}\right)$$

Since \frac{9}{24} and \frac{32}{24} have the same denominator, add them by adding their numerators.

$$\frac{9+32}{24}-2\left(\frac{1}{3}-\frac{2}{6}\right)$$

Add 9 and 32 to get 41.

$$\frac{41}{24}-2\left(\frac{1}{3}-\frac{2}{6}\right)$$

Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.

$$\frac{41}{24}-2\left(\frac{1}{3}-\frac{1}{3}\right)$$

Subtract \frac{1}{3} from \frac{1}{3} to get 0.

$$\frac{41}{24}-2\times 0$$

Multiply 2 and 0 to get 0.

$$\frac{41}{24}-0$$

Subtract 0 from \frac{41}{24} to get \frac{41}{24}.

$$\frac{41}{24}$$

Factor

$$\frac{41}{2 ^ {3} \cdot 3} = 1\frac{17}{24} = 1.7083333333333333$$