Solve 3/8+1/12quad1-1/2

$$\frac { 3 } { 8 } + \frac { 1 } { 12 } \quad 1 - \frac { 1 } { 2 }$$

Evaluate

$$-\frac{1}{24}\approx -0.041666667$$

Solution Steps

Multiply \frac{1}{12} and 1 to get \frac{1}{12}.

$$\frac{3}{8}+\frac{1}{12}-\frac{1}{2}$$

Least common multiple of 8 and 12 is 24. Convert \frac{3}{8} and \frac{1}{12} to fractions with denominator 24.

$$\frac{9}{24}+\frac{2}{24}-\frac{1}{2}$$

Since \frac{9}{24} and \frac{2}{24} have the same denominator, add them by adding their numerators.

$$\frac{9+2}{24}-\frac{1}{2}$$

Add 9 and 2 to get 11.

$$\frac{11}{24}-\frac{1}{2}$$

Least common multiple of 24 and 2 is 24. Convert \frac{11}{24} and \frac{1}{2} to fractions with denominator 24.

$$\frac{11}{24}-\frac{12}{24}$$

Since \frac{11}{24} and \frac{12}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{11-12}{24}$$

Subtract 12 from 11 to get -1.

$$-\frac{1}{24}$$

Factor

$$-\frac{1}{24} = -0.041666666666666664$$