Solve 3/5*2/9=3*2/5*9=6/45

$$\frac { 3 } { 5 } \times \frac { 2 } { 9 } = \frac { 3 \times 2 } { 5 \times 9 } = \frac { 6 } { 45 }$$

Verify

Solution Steps

Multiply \frac{3}{5} times \frac{2}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 2}{5\times 9}=\frac{3\times 2}{5\times 9}\text{ and }\frac{3\times 2}{5\times 9}=\frac{6}{45}$$

Do the multiplications in the fraction \frac{3\times 2}{5\times 9}.

$$\frac{6}{45}=\frac{3\times 2}{5\times 9}\text{ and }\frac{3\times 2}{5\times 9}=\frac{6}{45}$$

Reduce the fraction \frac{6}{45} to lowest terms by extracting and canceling out 3.

$$\frac{2}{15}=\frac{3\times 2}{5\times 9}\text{ and }\frac{3\times 2}{5\times 9}=\frac{6}{45}$$

Cancel out 3 in both numerator and denominator.

$$\frac{2}{15}=\frac{2}{3\times 5}\text{ and }\frac{3\times 2}{5\times 9}=\frac{6}{45}$$

Multiply 3 and 5 to get 15.

$$\frac{2}{15}=\frac{2}{15}\text{ and }\frac{3\times 2}{5\times 9}=\frac{6}{45}$$

Compare \frac{2}{15} and \frac{2}{15}.

$$\text{true}\text{ and }\frac{3\times 2}{5\times 9}=\frac{6}{45}$$

Cancel out 3 in both numerator and denominator.

$$\text{true}\text{ and }\frac{2}{3\times 5}=\frac{6}{45}$$

Multiply 3 and 5 to get 15.

$$\text{true}\text{ and }\frac{2}{15}=\frac{6}{45}$$

Reduce the fraction \frac{6}{45} to lowest terms by extracting and canceling out 3.

$$\text{true}\text{ and }\frac{2}{15}=\frac{2}{15}$$

Compare \frac{2}{15} and \frac{2}{15}.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$