Solve for a
a=\frac{5\left(h+17\right)}{3}
h\neq -17
Solve for h
h=\frac{3a}{5}-17
a\neq 0
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3a=5\left(h+17\right)
Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 5a, the least common multiple of 5,a.
3a=5h+85
Use the distributive property to multiply 5 by h+17.
\frac{3a}{3}=\frac{5h+85}{3}
Divide both sides by 3.
a=\frac{5h+85}{3}
Dividing by 3 undoes the multiplication by 3.
a=\frac{5h+85}{3}\text{, }a\neq 0
Variable a cannot be equal to 0.
3a=5\left(h+17\right)
Multiply both sides of the equation by 5a, the least common multiple of 5,a.
3a=5h+85
Use the distributive property to multiply 5 by h+17.
5h+85=3a
Swap sides so that all variable terms are on the left hand side.
5h=3a-85
Subtract 85 from both sides.
\frac{5h}{5}=\frac{3a-85}{5}
Divide both sides by 5.
h=\frac{3a-85}{5}
Dividing by 5 undoes the multiplication by 5.
h=\frac{3a}{5}-17
Divide 3a-85 by 5.
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