Solve 3/4x+2y=1..7

$$\frac { 3 } { 4 } x + 2 y = 1 . .7$$

Solve for x

$$x=\frac{4-8y}{3}$$

Steps for Solving Linear Equation

Subtract 2y from both sides.

$$\frac{3}{4}x=1-2y$$

Divide both sides of the equation by \frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{4}x}{\frac{3}{4}}=\frac{1-2y}{\frac{3}{4}}$$

Dividing by \frac{3}{4} undoes the multiplication by \frac{3}{4}.

$$x=\frac{1-2y}{\frac{3}{4}}$$

Divide 1-2y by \frac{3}{4} by multiplying 1-2y by the reciprocal of \frac{3}{4}.

$$x=\frac{4-8y}{3}$$

Solve for y

$$y=-\frac{3x}{8}+\frac{1}{2}$$

Steps for Solving Linear Equation

Subtract \frac{3}{4}x from both sides.

$$2y=1-\frac{3}{4}x$$

The equation is in standard form.

$$2y=-\frac{3x}{4}+1$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{-\frac{3x}{4}+1}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{-\frac{3x}{4}+1}{2}$$

Divide 1-\frac{3x}{4} by 2.

$$y=-\frac{3x}{8}+\frac{1}{2}$$