Solve for a
a=12
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\frac{3}{4}a-3-\frac{1}{2}a=0
Subtract \frac{1}{2}a from both sides.
\frac{1}{4}a-3=0
Combine \frac{3}{4}a and -\frac{1}{2}a to get \frac{1}{4}a.
\frac{1}{4}a=3
Add 3 to both sides. Anything plus zero gives itself.
a=3\times 4
Multiply both sides by 4, the reciprocal of \frac{1}{4}.
a=12
Multiply 3 and 4 to get 12.
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