Solve 3/4*(14/3)^2-3*14/3+4

$$\frac { 3 } { 4 } \times ( \frac { 14 } { 3 } ) ^ { 2 } - 3 \times \frac { 14 } { 3 } + 4$$

Evaluate

$$\frac{19}{3}\approx 6.333333333$$

Solution Steps

Calculate \frac{14}{3} to the power of 2 and get \frac{196}{9}.

$$\frac{3}{4}\times \frac{196}{9}-3\times \frac{14}{3}+4$$

Multiply \frac{3}{4} times \frac{196}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 196}{4\times 9}-3\times \frac{14}{3}+4$$

Do the multiplications in the fraction \frac{3\times 196}{4\times 9}.

$$\frac{588}{36}-3\times \frac{14}{3}+4$$

Reduce the fraction \frac{588}{36} to lowest terms by extracting and canceling out 12.

$$\frac{49}{3}-3\times \frac{14}{3}+4$$

Cancel out 3 and 3.

$$\frac{49}{3}-14+4$$

Convert 14 to fraction \frac{42}{3}.

$$\frac{49}{3}-\frac{42}{3}+4$$

Since \frac{49}{3} and \frac{42}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-42}{3}+4$$

Subtract 42 from 49 to get 7.

$$\frac{7}{3}+4$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{7}{3}+\frac{12}{3}$$

Since \frac{7}{3} and \frac{12}{3} have the same denominator, add them by adding their numerators.

$$\frac{7+12}{3}$$

Add 7 and 12 to get 19.

$$\frac{19}{3}$$

Factor

$$\frac{19}{3} = 6\frac{1}{3} = 6.333333333333333$$