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2\times \frac{\frac{3}{4}}{\frac{1\times 2+1}{2}}\left(2\times 3+1\right)-3=2
Multiply both sides of the equation by 6, the least common multiple of 3,2.
2\times \frac{3\times 2}{4\left(1\times 2+1\right)}\left(2\times 3+1\right)-3=2
Divide \frac{3}{4} by \frac{1\times 2+1}{2} by multiplying \frac{3}{4} by the reciprocal of \frac{1\times 2+1}{2}.
2\times \frac{3}{2\left(1+2\right)}\left(2\times 3+1\right)-3=2
Cancel out 2 in both numerator and denominator.
2\times \frac{3}{2\times 3}\left(2\times 3+1\right)-3=2
Add 1 and 2 to get 3.
2\times \frac{3}{6}\left(2\times 3+1\right)-3=2
Multiply 2 and 3 to get 6.
2\times \frac{1}{2}\left(2\times 3+1\right)-3=2
Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.
2\times 3+1-3=2
Cancel out 2 and 2.
6+1-3=2
Multiply 2 and 3 to get 6.
7-3=2
Add 6 and 1 to get 7.
4=2
Subtract 3 from 7 to get 4.
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Compare 4 and 2.