Solve 3/4*[6/5-2/7*(1+2/5)]=

$$\frac { 3 } { 4 } \cdot [ \frac { 6 } { 5 } - \frac { 2 } { 7 } \cdot ( 1 + \frac { 2 } { 5 } ) ] =$$

Evaluate

$$\frac{3}{5}=0.6$$

Solution Steps

Convert 1 to fraction \frac{5}{5}.

$$\frac{3}{4}\left(\frac{6}{5}-\frac{2}{7}\left(\frac{5}{5}+\frac{2}{5}\right)\right)$$

Since \frac{5}{5} and \frac{2}{5} have the same denominator, add them by adding their numerators.

$$\frac{3}{4}\left(\frac{6}{5}-\frac{2}{7}\times \frac{5+2}{5}\right)$$

Add 5 and 2 to get 7.

$$\frac{3}{4}\left(\frac{6}{5}-\frac{2}{7}\times \frac{7}{5}\right)$$

Multiply \frac{2}{7} times \frac{7}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{4}\left(\frac{6}{5}-\frac{2\times 7}{7\times 5}\right)$$

Cancel out 7 in both numerator and denominator.

$$\frac{3}{4}\left(\frac{6}{5}-\frac{2}{5}\right)$$

Since \frac{6}{5} and \frac{2}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{4}\times \frac{6-2}{5}$$

Subtract 2 from 6 to get 4.

$$\frac{3}{4}\times \frac{4}{5}$$

Multiply \frac{3}{4} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 4}{4\times 5}$$

Cancel out 4 in both numerator and denominator.

$$\frac{3}{5}$$

Factor

$$\frac{3}{5} = 0.6$$