Solve 3/3-2*(-1/3)+-1/3

$$\frac { 3 } { 3 } - 2 \cdot ( - \frac { 1 } { 3 } ) + - \frac { 1 } { 3 }$$

Evaluate

$$\frac{4}{3}\approx 1.333333333$$

Solution Steps

Divide 3 by 3 to get 1.

$$1-2\left(-\frac{1}{3}\right)-\frac{1}{3}$$

Express 2\left(-\frac{1}{3}\right) as a single fraction.

$$1-\frac{2\left(-1\right)}{3}-\frac{1}{3}$$

Multiply 2 and -1 to get -2.

$$1-\frac{-2}{3}-\frac{1}{3}$$

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$1-\left(-\frac{2}{3}\right)-\frac{1}{3}$$

The opposite of -\frac{2}{3} is \frac{2}{3}.

$$1+\frac{2}{3}-\frac{1}{3}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{3}{3}+\frac{2}{3}-\frac{1}{3}$$

Since \frac{3}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{3+2}{3}-\frac{1}{3}$$

Add 3 and 2 to get 5.

$$\frac{5}{3}-\frac{1}{3}$$

Since \frac{5}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-1}{3}$$

Subtract 1 from 5 to get 4.

$$\frac{4}{3}$$

Factor

$$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$$