Solve 3/3+6-12-6/6^2+8-6+2/6-2

$$\frac { 3 } { 3 + 6 } - \frac { 12 - 6 } { 6 ^ { 2 } + 8 - 6 } + \frac { 2 } { 6 - 2 }$$

Evaluate

$$\frac{77}{114}\approx 0.675438596$$

Solution Steps

Add 3 and 6 to get 9.

$$\frac{3}{9}-\frac{12-6}{6^{2}+8-6}+\frac{2}{6-2}$$

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$\frac{1}{3}-\frac{12-6}{6^{2}+8-6}+\frac{2}{6-2}$$

Subtract 6 from 12 to get 6.

$$\frac{1}{3}-\frac{6}{6^{2}+8-6}+\frac{2}{6-2}$$

Calculate 6 to the power of 2 and get 36.

$$\frac{1}{3}-\frac{6}{36+8-6}+\frac{2}{6-2}$$

Add 36 and 8 to get 44.

$$\frac{1}{3}-\frac{6}{44-6}+\frac{2}{6-2}$$

Subtract 6 from 44 to get 38.

$$\frac{1}{3}-\frac{6}{38}+\frac{2}{6-2}$$

Reduce the fraction \frac{6}{38} to lowest terms by extracting and canceling out 2.

$$\frac{1}{3}-\frac{3}{19}+\frac{2}{6-2}$$

Least common multiple of 3 and 19 is 57. Convert \frac{1}{3} and \frac{3}{19} to fractions with denominator 57.

$$\frac{19}{57}-\frac{9}{57}+\frac{2}{6-2}$$

Since \frac{19}{57} and \frac{9}{57} have the same denominator, subtract them by subtracting their numerators.

$$\frac{19-9}{57}+\frac{2}{6-2}$$

Subtract 9 from 19 to get 10.

$$\frac{10}{57}+\frac{2}{6-2}$$

Subtract 2 from 6 to get 4.

$$\frac{10}{57}+\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{10}{57}+\frac{1}{2}$$

Least common multiple of 57 and 2 is 114. Convert \frac{10}{57} and \frac{1}{2} to fractions with denominator 114.

$$\frac{20}{114}+\frac{57}{114}$$

Since \frac{20}{114} and \frac{57}{114} have the same denominator, add them by adding their numerators.

$$\frac{20+57}{114}$$

Add 20 and 57 to get 77.

$$\frac{77}{114}$$

Factor

$$\frac{7 \cdot 11}{2 \cdot 3 \cdot 19} = 0.6754385964912281$$