Solve 3/28b+3/b+1

$$\frac { 3 } { 28 b } + \frac { 3 } { b + 1 }$$

Evaluate

$$\frac{3\left(29b+1\right)}{28b\left(b+1\right)}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 28b and b+1 is 28b\left(b+1\right). Multiply \frac{3}{28b} times \frac{b+1}{b+1}. Multiply \frac{3}{b+1} times \frac{28b}{28b}.

$$\frac{3\left(b+1\right)}{28b\left(b+1\right)}+\frac{3\times 28b}{28b\left(b+1\right)}$$

Since \frac{3\left(b+1\right)}{28b\left(b+1\right)} and \frac{3\times 28b}{28b\left(b+1\right)} have the same denominator, add them by adding their numerators.

$$\frac{3\left(b+1\right)+3\times 28b}{28b\left(b+1\right)}$$

Do the multiplications in 3\left(b+1\right)+3\times 28b.

$$\frac{3b+3+84b}{28b\left(b+1\right)}$$

Combine like terms in 3b+3+84b.

$$\frac{87b+3}{28b\left(b+1\right)}$$

Expand 28b\left(b+1\right).

$$\frac{87b+3}{28b^{2}+28b}$$

Factor

$$\frac{3\left(29b+1\right)}{28b\left(b+1\right)}$$