Solve 3/2-3*(-1/2)+1-4=

$$\frac { 3 } { 2 } - 3 \cdot ( - \frac { 1 } { 2 } ) + 1 - 4 =$$

Evaluate

$$0$$

Solution Steps

Express 3\left(-\frac{1}{2}\right) as a single fraction.

$$\frac{3}{2}-\frac{3\left(-1\right)}{2}+1-4$$

Multiply 3 and -1 to get -3.

$$\frac{3}{2}-\frac{-3}{2}+1-4$$

Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$\frac{3}{2}-\left(-\frac{3}{2}\right)+1-4$$

The opposite of -\frac{3}{2} is \frac{3}{2}.

$$\frac{3}{2}+\frac{3}{2}+1-4$$

Since \frac{3}{2} and \frac{3}{2} have the same denominator, add them by adding their numerators.

$$\frac{3+3}{2}+1-4$$

Add 3 and 3 to get 6.

$$\frac{6}{2}+1-4$$

Divide 6 by 2 to get 3.

$$3+1-4$$

Add 3 and 1 to get 4.

$$4-4$$

Subtract 4 from 4 to get 0.

$$0$$

Factor

$$0$$