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\frac{3}{2}\sqrt{4^{2}\times 6}+\sqrt[4]{2\times 3^{5}}-2\sqrt[4]{2\times 2}+\sqrt[4]{3^{4}\times 3}
To multiply powers of the same base, add their exponents. Add 4 and 1 to get 5.
\frac{3}{2}\sqrt{4^{2}\times 6}+\sqrt[4]{2\times 3^{5}}-2\sqrt[4]{2\times 2}+\sqrt[4]{3^{5}}
To multiply powers of the same base, add their exponents. Add 4 and 1 to get 5.
\frac{3}{2}\sqrt{16\times 6}+\sqrt[4]{2\times 3^{5}}-2\sqrt[4]{2\times 2}+\sqrt[4]{3^{5}}
Calculate 4 to the power of 2 and get 16.
\frac{3}{2}\sqrt{96}+\sqrt[4]{2\times 3^{5}}-2\sqrt[4]{2\times 2}+\sqrt[4]{3^{5}}
Multiply 16 and 6 to get 96.
\frac{3}{2}\times 4\sqrt{6}+\sqrt[4]{2\times 3^{5}}-2\sqrt[4]{2\times 2}+\sqrt[4]{3^{5}}
Factor 96=4^{2}\times 6. Rewrite the square root of the product \sqrt{4^{2}\times 6} as the product of square roots \sqrt{4^{2}}\sqrt{6}. Take the square root of 4^{2}.
6\sqrt{6}+\sqrt[4]{2\times 3^{5}}-2\sqrt[4]{2\times 2}+\sqrt[4]{3^{5}}
Multiply \frac{3}{2} and 4 to get 6.
6\sqrt{6}+\sqrt[4]{2\times 243}-2\sqrt[4]{2\times 2}+\sqrt[4]{3^{5}}
Calculate 3 to the power of 5 and get 243.
6\sqrt{6}+\sqrt[4]{486}-2\sqrt[4]{2\times 2}+\sqrt[4]{3^{5}}
Multiply 2 and 243 to get 486.
6\sqrt{6}+\sqrt[4]{486}-2\sqrt[4]{4}+\sqrt[4]{3^{5}}
Multiply 2 and 2 to get 4.
\sqrt[4]{4}=\sqrt[4]{2^{2}}=2^{\frac{2}{4}}=2^{\frac{1}{2}}=\sqrt{2}
Rewrite \sqrt[4]{4} as \sqrt[4]{2^{2}}. Convert from radical to exponential form and cancel out 2 in the exponent. Convert back to radical form.
6\sqrt{6}+\sqrt[4]{486}-2\sqrt{2}+\sqrt[4]{3^{5}}
Insert the obtained value back in the expression.
6\sqrt{6}+\sqrt[4]{486}-2\sqrt{2}+\sqrt[4]{243}
Calculate 3 to the power of 5 and get 243.