Solve 3/-24-2/-36=-10/144

$$\frac { 3 } { - 24 } - \frac { 2 } { - 36 } = \frac { - 10 } { 144 }$$

Verify

Solution Steps

Reduce the fraction \frac{3}{-24} to lowest terms by extracting and canceling out 3.

$$-\frac{1}{8}-\frac{2}{-36}=\frac{-10}{144}$$

Reduce the fraction \frac{2}{-36} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{8}-\left(-\frac{1}{18}\right)=\frac{-10}{144}$$

The opposite of -\frac{1}{18} is \frac{1}{18}.

$$-\frac{1}{8}+\frac{1}{18}=\frac{-10}{144}$$

Least common multiple of 8 and 18 is 72. Convert -\frac{1}{8} and \frac{1}{18} to fractions with denominator 72.

$$-\frac{9}{72}+\frac{4}{72}=\frac{-10}{144}$$

Since -\frac{9}{72} and \frac{4}{72} have the same denominator, add them by adding their numerators.

$$\frac{-9+4}{72}=\frac{-10}{144}$$

Add -9 and 4 to get -5.

$$-\frac{5}{72}=\frac{-10}{144}$$

Reduce the fraction \frac{-10}{144} to lowest terms by extracting and canceling out 2.

$$-\frac{5}{72}=-\frac{5}{72}$$

Compare -\frac{5}{72} and -\frac{5}{72}.

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