Solve for x
x = \frac{81}{80} = 1\frac{1}{80} = 1.0125
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\frac{4}{9}x\times \frac{3\times 3+1}{3}=\frac{1\times 2+1}{2}
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
\frac{4}{9}x\times \frac{9+1}{3}=\frac{1\times 2+1}{2}
Multiply 3 and 3 to get 9.
\frac{4}{9}x\times \frac{10}{3}=\frac{1\times 2+1}{2}
Add 9 and 1 to get 10.
\frac{4\times 10}{9\times 3}x=\frac{1\times 2+1}{2}
Multiply \frac{4}{9} times \frac{10}{3} by multiplying numerator times numerator and denominator times denominator.
\frac{40}{27}x=\frac{1\times 2+1}{2}
Do the multiplications in the fraction \frac{4\times 10}{9\times 3}.
\frac{40}{27}x=\frac{2+1}{2}
Multiply 1 and 2 to get 2.
\frac{40}{27}x=\frac{3}{2}
Add 2 and 1 to get 3.
x=\frac{3}{2}\times \frac{27}{40}
Multiply both sides by \frac{27}{40}, the reciprocal of \frac{40}{27}.
x=\frac{3\times 27}{2\times 40}
Multiply \frac{3}{2} times \frac{27}{40} by multiplying numerator times numerator and denominator times denominator.
x=\frac{81}{80}
Do the multiplications in the fraction \frac{3\times 27}{2\times 40}.
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