Solve frac{3^{4}*2^7*2^5}{27(2^3)^3}=

$$\frac { 3 ^ { 4 } \cdot 2 ^ { 7 } \cdot 2 ^ { 5 } } { 27 ( 2 ^ { 3 } ) ^ { 3 } } =$$

Evaluate

$$24$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 7 and 5 to get 12.

$$\frac{3^{4}\times 2^{12}}{27\times \left(2^{3}\right)^{3}}$$

To raise a power to another power, multiply the exponents. Multiply 3 and 3 to get 9.

$$\frac{3^{4}\times 2^{12}}{27\times 2^{9}}$$

Cancel out 2^{9} in both numerator and denominator.

$$\frac{2^{3}\times 3^{4}}{27}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{8\times 3^{4}}{27}$$

Calculate 3 to the power of 4 and get 81.

$$\frac{8\times 81}{27}$$

Multiply 8 and 81 to get 648.

$$\frac{648}{27}$$

Divide 648 by 27 to get 24.

$$24$$

Factor

$$2^{3}\times 3$$