Solve 3^-3/3^2*2^-3

$$\frac { 3 ^ { - 3 } } { 3 ^ { 2 } \cdot 2 ^ { - 3 } }$$

Evaluate

$$\frac{8}{243}\approx 0.032921811$$

Solution Steps

To divide powers of the same base, subtract the numerator's exponent from the denominator's exponent.

$$\frac{1}{2^{-3}\times 3^{5}}$$

Calculate 2 to the power of -3 and get \frac{1}{8}.

$$\frac{1}{\frac{1}{8}\times 3^{5}}$$

Calculate 3 to the power of 5 and get 243.

$$\frac{1}{\frac{1}{8}\times 243}$$

Multiply \frac{1}{8} and 243 to get \frac{243}{8}.

$$\frac{1}{\frac{243}{8}}$$

Divide 1 by \frac{243}{8} by multiplying 1 by the reciprocal of \frac{243}{8}.

$$1\times \frac{8}{243}$$

Multiply 1 and \frac{8}{243} to get \frac{8}{243}.

$$\frac{8}{243}$$

Factor

$$\frac{2 ^ {3}}{3 ^ {5}} = 0.03292181069958848$$