Solve 3+1/3/5-frac{3{4}}

$$\frac { 3 + \frac { 1 } { 3 } } { 5 - \frac { 3 } { 4 } }$$

Evaluate

$$\frac{40}{51}\approx 0.784313725$$

Solution Steps

Convert 3 to fraction \frac{9}{3}.

$$\frac{\frac{9}{3}+\frac{1}{3}}{5-\frac{3}{4}}$$

Since \frac{9}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{9+1}{3}}{5-\frac{3}{4}}$$

Add 9 and 1 to get 10.

$$\frac{\frac{10}{3}}{5-\frac{3}{4}}$$

Convert 5 to fraction \frac{20}{4}.

$$\frac{\frac{10}{3}}{\frac{20}{4}-\frac{3}{4}}$$

Since \frac{20}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{10}{3}}{\frac{20-3}{4}}$$

Subtract 3 from 20 to get 17.

$$\frac{\frac{10}{3}}{\frac{17}{4}}$$

Divide \frac{10}{3} by \frac{17}{4} by multiplying \frac{10}{3} by the reciprocal of \frac{17}{4}.

$$\frac{10}{3}\times \frac{4}{17}$$

Multiply \frac{10}{3} times \frac{4}{17} by multiplying numerator times numerator and denominator times denominator.

$$\frac{10\times 4}{3\times 17}$$

Do the multiplications in the fraction \frac{10\times 4}{3\times 17}.

$$\frac{40}{51}$$

Factor

$$\frac{2 ^ {3} \cdot 5}{3 \cdot 17} = 0.7843137254901961$$