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Real Part
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\frac{\left(25+i\right)i}{1i^{2}}
Multiply both numerator and denominator by imaginary unit i.
\frac{\left(25+i\right)i}{-1}
By definition, i^{2} is -1. Calculate the denominator.
\frac{25i+i^{2}}{-1}
Multiply 25+i times i.
\frac{25i-1}{-1}
By definition, i^{2} is -1.
\frac{-1+25i}{-1}
Reorder the terms.
1-25i
Divide -1+25i by -1 to get 1-25i.
Re(\frac{\left(25+i\right)i}{1i^{2}})
Multiply both numerator and denominator of \frac{25+i}{i} by imaginary unit i.
Re(\frac{\left(25+i\right)i}{-1})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{25i+i^{2}}{-1})
Multiply 25+i times i.
Re(\frac{25i-1}{-1})
By definition, i^{2} is -1.
Re(\frac{-1+25i}{-1})
Reorder the terms.
Re(1-25i)
Divide -1+25i by -1 to get 1-25i.
1
The real part of 1-25i is 1.