Solve 24/9+16/8+4/3=

$$\frac { 24 } { 9 } + \frac { 16 } { 8 } + \frac { 4 } { 3 } =$$

Evaluate

$$6$$

Solution Steps

Reduce the fraction \frac{24}{9} to lowest terms by extracting and canceling out 3.

$$\frac{8}{3}+\frac{16}{8}+\frac{4}{3}$$

Divide 16 by 8 to get 2.

$$\frac{8}{3}+2+\frac{4}{3}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{8}{3}+\frac{6}{3}+\frac{4}{3}$$

Since \frac{8}{3} and \frac{6}{3} have the same denominator, add them by adding their numerators.

$$\frac{8+6}{3}+\frac{4}{3}$$

Add 8 and 6 to get 14.

$$\frac{14}{3}+\frac{4}{3}$$

Since \frac{14}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$\frac{14+4}{3}$$

Add 14 and 4 to get 18.

$$\frac{18}{3}$$

Divide 18 by 3 to get 6.

$$6$$

Factor

$$2\times 3$$