Solve 23/24x+1/3=4+1/6

$$\frac { 23 } { 24 } x + \frac { 1 } { 3 } = 4 + \frac { 1 } { 6 }$$

Solve for x

$$x=4$$

Steps for Solving Linear Equation

Convert 4 to fraction \frac{24}{6}.

$$\frac{23}{24}x+\frac{1}{3}=\frac{24}{6}+\frac{1}{6}$$

Since \frac{24}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{23}{24}x+\frac{1}{3}=\frac{24+1}{6}$$

Add 24 and 1 to get 25.

$$\frac{23}{24}x+\frac{1}{3}=\frac{25}{6}$$

Subtract \frac{1}{3} from both sides.

$$\frac{23}{24}x=\frac{25}{6}-\frac{1}{3}$$

Least common multiple of 6 and 3 is 6. Convert \frac{25}{6} and \frac{1}{3} to fractions with denominator 6.

$$\frac{23}{24}x=\frac{25}{6}-\frac{2}{6}$$

Since \frac{25}{6} and \frac{2}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{23}{24}x=\frac{25-2}{6}$$

Subtract 2 from 25 to get 23.

$$\frac{23}{24}x=\frac{23}{6}$$

Multiply both sides by \frac{24}{23}, the reciprocal of \frac{23}{24}.

$$x=\frac{23}{6}\times \frac{24}{23}$$

Multiply \frac{23}{6} times \frac{24}{23} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{23\times 24}{6\times 23}$$

Cancel out 23 in both numerator and denominator.

$$x=\frac{24}{6}$$

Divide 24 by 6 to get 4.

$$x=4$$