Solve 2004^3-2*2004^2-2000/2004^3+2004^2-2005

$$\frac { 2004 ^ { 3 } - 2 \times 2004 ^ { 2 } - 2000 } { 2004 ^ { 3 } + 2004 ^ { 2 } - 2005 }$$

Evaluate

$$\frac{8040062032}{8052110075}\approx 0.998503741$$

Solution Steps

Calculate 2004 to the power of 3 and get 8048096064.

$$\frac{8048096064-2\times 2004^{2}-2000}{2004^{3}+2004^{2}-2005}$$

Calculate 2004 to the power of 2 and get 4016016.

$$\frac{8048096064-2\times 4016016-2000}{2004^{3}+2004^{2}-2005}$$

Multiply 2 and 4016016 to get 8032032.

$$\frac{8048096064-8032032-2000}{2004^{3}+2004^{2}-2005}$$

Subtract 8032032 from 8048096064 to get 8040064032.

$$\frac{8040064032-2000}{2004^{3}+2004^{2}-2005}$$

Subtract 2000 from 8040064032 to get 8040062032.

$$\frac{8040062032}{2004^{3}+2004^{2}-2005}$$

Calculate 2004 to the power of 3 and get 8048096064.

$$\frac{8040062032}{8048096064+2004^{2}-2005}$$

Calculate 2004 to the power of 2 and get 4016016.

$$\frac{8040062032}{8048096064+4016016-2005}$$

Add 8048096064 and 4016016 to get 8052112080.

$$\frac{8040062032}{8052112080-2005}$$

Subtract 2005 from 8052112080 to get 8052110075.

$$\frac{8040062032}{8052110075}$$

Factor

$$\frac{2 ^ {4} \cdot 233 \cdot 2156669}{5 ^ {2} \cdot 401 ^ {2} \cdot 2003} = 0.9985037408967612$$