Solve 20x^5/4x^2=5x^3

$$\frac { 20 x ^ { 5 } } { 4 x ^ { 2 } } = 5 x ^ { 3 }$$

Solve for x

$$x\neq 0$$

Solution Steps

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 4x^{2}.

$$20x^{5}=5x^{3}\times 4x^{2}$$

To multiply powers of the same base, add their exponents. Add 3 and 2 to get 5.

$$20x^{5}=5x^{5}\times 4$$

Multiply 5 and 4 to get 20.

$$20x^{5}=20x^{5}$$

Subtract 20x^{5} from both sides.

$$20x^{5}-20x^{5}=0$$

Combine 20x^{5} and -20x^{5} to get 0.

$$0=0$$

Compare 0 and 0.

$$\text{true}$$

This is true for any x.

$$x\in \mathrm{R}$$

Variable x cannot be equal to 0.

$$x\in \mathrm{R}\setminus 0$$