Solve 20^2+31^2-21^2/2*20*31

$$\frac { 20 ^ { 2 } + 31 ^ { 2 } - 21 ^ { 2 } } { 2 \times 20 \times 31 }$$

Evaluate

$$\frac{23}{31}\approx 0.741935484$$

Solution Steps

Calculate 20 to the power of 2 and get 400.

$$\frac{400+31^{2}-21^{2}}{2\times 20\times 31}$$

Calculate 31 to the power of 2 and get 961.

$$\frac{400+961-21^{2}}{2\times 20\times 31}$$

Add 400 and 961 to get 1361.

$$\frac{1361-21^{2}}{2\times 20\times 31}$$

Calculate 21 to the power of 2 and get 441.

$$\frac{1361-441}{2\times 20\times 31}$$

Subtract 441 from 1361 to get 920.

$$\frac{920}{2\times 20\times 31}$$

Multiply 2 and 20 to get 40.

$$\frac{920}{40\times 31}$$

Multiply 40 and 31 to get 1240.

$$\frac{920}{1240}$$

Reduce the fraction \frac{920}{1240} to lowest terms by extracting and canceling out 40.

$$\frac{23}{31}$$

Factor

$$\frac{23}{31} = 0.7419354838709677$$